bangla natok

SQL-query:

MySQL retourneerde:

#1064 – You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '<?php } else {
$dbhost = 'localhost'' at line 1 '

What could I have done wrong? Thanks in advance.

I am baffled though, why didn't the original code 'work out of the box'? Is it something wrong with Wamp? Should I be using something else to do these tutorials with?

Thanks again.

list($count) = mysql_fetch_row($result);
if($count >= 1) { ?>

Move the following line:

<span style='color:red'>Error: that username is taken.</span>

to go inside my if block:

if($result) { ?>
<span style='color:red'>Error: that username is taken.</span>
<?php }

Notice that you now have two “else” blocks, delete the one closest to the if, the one which have no code inside the { }:

else {
}

—————–
The code should then look like this:
…..
$query = sprintf(”SELECT * FROM users WHERE username = '%s'”,
mysql_real_escape_string($_POST['username']));
$result = mysql_query($query);
if($result) { ?>
<span style='color:red'>Error: that username is taken.</span>
<?php } else {
$query = sprintf(”INSERT INTO users(username,password) VALUES ('%s','%s');”,
mysql_real_escape_string($_POST['username']),
mysql_real_escape_string(md5($password)));
mysql_query($query);
?>
<span style='color:green'>Congratulations, you registered successfully!</span>
<?php
}
}
}
?>

——————————–
<?php
if($_POST) {
$password = $_POST['password'];
$confirm = $_POST['confirm'];
if($password != $confirm) { ?>
<span style='color:red'>Error: Passwords do not match!</span>
<?php } else {
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'BBG';
require_once 'config.php';
$conn = mysql_connect($dbhost,$dbuser,$dbpass)
or die ('Error connecting to mysql');
mysql_select_db($dbname);
$query = sprintf(”SELECT * FROM users WHERE username = '%s'”,
mysql_real_escape_string($_POST['username']));
$result = mysql_query($query);
if($result) {
} else {
}
list($count) = mysql_fetch_row($result);
if($count >= 1) { ?>
<span style='color:red'>Error: that username is taken.</span>
<?php } else {
$query = sprintf(”INSERT INTO users(username,password) VALUES ('%s','%s');”,
mysql_real_escape_string($_POST['username']),
mysql_real_escape_string(md5($password)));
mysql_query($query);
?>
<span style='color:green'>Congratulations, you registered successfully!</span>
<?php
}
}
}
?>
<form method='post' action='register.php'>Username: <input type='text' name='username' />

Password: <input type='password' name='password' />

Confirm Password: <input type='password' name='confirm' />

<input type='submit' value='Register!' />
</form>
——————————

The error message has changed, now it says 'Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in C:wampwwwBBGregister.php on line 22'.

Line 22 is this one: list($count) = mysql_fetch_row($result);

I know I've done something wrong, but I feel I'm very close to getting this working. Can you see where I've messed up?

$query = sprintf(”SELECT * FROM users WHERE username = '%s'”, mysql_real_escape_string($_POST['username'])));
$result = mysql_fetch_array(mysql_query($isuser));

Then I use a simple if statement to check if I got any data or not:
if($result) {
// User already exists
} else {
// User does not exist, safe to register if all input validates
}

$result is an array, and if the user exists in the DB I have data there and the if check returns true, if no data enters the array is empty and the if check returns false and runs the else statement instead.

<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'db_name';
?>

Now it's working, but I'm getting a new error:

Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in C:wampwwwBBGregister.php on line 19

This is line 19: list($count) = mysql_fetch_row($result);

I see that Marius had the same problem and managed to solve it, but he didn't post his solution .

Anybody have any ideas?